The number of 10 digits that can be formed using the digits 0, 1, 2, 3………..9 without repetition is ____.

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Concept- The number of ten-digit numbers that can be formed using the given digits is equal to the number of possible arrangements of the digits, with the exception of those in which 0 appears in the first place. Note that the number of digits given is 10, and we are asked how many ten-digit numbers can be formed using these digits
Given that there are 10 digits, how many ten-digit numbers can be formed using these digits? The answer is that there are as many arrangements of the digits as there are ten digits, with the exception of those in which 0 comes before any other digits, in which case the answer would be a nine-digit number. In order to deduct the instances where zero first appeared, we will first discover all possible combinations of the digits provided in the query.
As a result, there are 10P10, or 10!, different ways that the provided numbers could be arranged.
Check to see if we can solve it now.
Now see if we fix the position of 0. We are left with 9 digits and 9 places to arrange them,
So, the number of arrangements in which 0 appears in the first place is 9P9,
which is equal to 9!.
Therefore, the number of 10 digit numbers that can be formed using the digits

0, 1, 2, 3 \dots \dots \dots . . 9 without repetition is (10! - 9!) (10! - 9!)

which is equal to 9! (10 - 1) = 9.9! 9! (10 - 1) = 9.9!

Hence, correct answer is

9.9!

.

The number of 10 digits that can be formed using the digits 0, 1, 2, 3………..9 without repetition is ____.

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