The number of all possible integral values of '$\mathrm{\alpha }$' for which the roots of the quadratic equation 6x² -11x + $\mathrm{\alpha }$ = 0 are rational numbers is

6x² - 11x + $\mathrm{\alpha }$ = 0 
Given the roots are rational 
$∆$ is perfect square 
121 - 24$\mathrm{\alpha }$ = $\mathrm{\lambda }$²
$\Rightarrow$maximum value of $\mathrm{\alpha }$ is 5
$\begin{array}{l}\mathrm{\alpha }=1\Rightarrow \mathrm{\lambda }\notin \mathrm{I}\\ \mathrm{\alpha }=2\Rightarrow \mathrm{\lambda }\notin \mathrm{I}\\ \mathrm{\alpha }=3\Rightarrow \mathrm{\lambda }\in \mathrm{I}\\ \mathrm{\alpha }=4\Rightarrow \mathrm{\lambda }\in \mathrm{I}\\ \mathrm{\alpha }=5\Rightarrow \mathrm{\lambda }\in \mathrm{I}\Rightarrow \end{array}$
3 integral values