The number of atoms in 140 grams of iron are

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$15 \times 10^{23}$

$30 \times 10^{23}$

$60 \times 10^{23}$

$45 \times 10^{23}$

answer is B.

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Detailed Solution

$\begin{array}{l} 1 mole \to 56 g of iron \to 6 \times 10^{23} \\ 140 g of iron \to x atoms of iron \\ 140 \times 6 \times 10^{23} = x \times 56 \\ x = \frac{140 \times 6 \times 10^{23}}{56} \\ = 15 \times 10^{23} \end{array}$

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