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The number of atoms in 7.4 moles of iron are

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$9.4 \times 10^{23}$

$22.2 \times 10^{23}$

$44 \times 10^{23}$

$44.4 \times 10^{23}$

answer is A.

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Detailed Solution

1 Mole iron has ${6.023×10}^{23} atoms$ of Fe.

Number of atoms present in 7.4 mol of iron is

$\frac{6.022 \times 10^{23} atoms}{1 mol Fe} \times 7.4 mol Fe = 44.5 \times 10^{23}$

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