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The number of common tangents of the circles $x^{2} + y^{2} - 4 = 0$ and $x^{2} + y^{2} - 6 x - 8 y - 24 = 0$ is

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Detailed Solution

$\begin{array}{l} C_{1} = (0, 0) and C_{2} = (3, 4) \\ r_{1} = 2 and r_{2} = 7 \\ C_{1} C_{2} = |r_{1} - r_{2}| \end{array}$
Given two touch each other internally No. of common tangents =1

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