The number of correct statements is / are correct. A mixture containing $64.0gr{H}_2\text{ and }64.0gr{O}_2$  is ignited. So that water is formed as follows :  $2H_2+O_2\to 2H_{2}O$

$H_2$  is the limiting reagent

$O_2$ is the limiting reagent

The reaction mixture contains  $72.0gr\text{\hspace{0.17em}of }{H}_{2}O$  and  $56.0gr\text{\hspace{0.17em}of unreacted }{H}_2$

The reaction mixture contains  $56.0gr\text{\hspace{0.17em}of }{H}_{2}O\text{ and }72gr\text{\hspace{0.17em}of unreacted }{H}_2$