Q.

The number of distinct terms in the expansion of  (x+y2)13+(x2+y)14 is _______

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answer is 28.

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Detailed Solution

To get common terms in both the expansions xr1(y2)13r1=(y)14r2(x2)r2

     r1=2r2  and262r1=14r2      r1=8,  r2=4

Only one term is common.

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