Q.

The number of distinct terms in the expansion of (x+2y3z+5w7u)n  is

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a

n+4Cn+2

b

n+1

c

2n

d

n+4C4

answer is B.

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Detailed Solution

Given expression (x+2y3z+5w7u)n

If the expression in the base have r distinct terms

Then the expression will have  n+r1Cr1 terms

Here the expression has 5th term and

Its expansion has  n+51C51

=n+4C4

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The number of distinct terms in the expansion of (x+2y−3z+5w−7u)n  is