The number of electorns delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on electron = 1.60 × 10^–19 C)  

Total number of coulombs passed = i x t = 1 x 60 = 60

$$\begin{gathered} \mathrm{No}. \mathrm{of} \mathrm{Electrons} \mathrm{transformed}=\frac{\mathrm{Total} \mathrm{coulombs} \mathrm{passed}}{\mathrm{Charge} \mathrm{on} \mathrm{electron} \mathrm{in} \mathrm{Coulomb}} \\ =\frac{60}{1.6\times {10}^{-19}} =3.75\times {10}^{-20} \end{gathered}$$