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Q.

The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is ?
(charge on electron = $1.60 \times 10^{- 19} C$ )

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a

$7.48 \times 10^{23}$

b

$3.75 \times 10^{20}$

c

$6 \times 10^{20}$

d

$6 \times 10^{23}$

answer is C.

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Detailed Solution

$Q = I \times t$

$Q = 1 \times 60 = 60 C$

${Now, 1.60×10}^{- 19} C \equiv 1 electron$

$∴ 60 C \equiv \frac{60}{1.6 \times 10^{- 19}} = 37.5 \times 10^{19} = 3.75 \times 10^{20} electrons$

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The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is ?(charge on electron = 1.60×10-19C)