The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charger on electron =1.60×10⁻¹⁹C)

A. 6×10²³

B. 6×10²⁰

C. 3.75×10²⁰

D. 7.48×10²³

To determine the number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds, we follow these steps:

Step 1: Calculate the total charge (Q) delivered

The total charge can be calculated using the formula:

Q = I × t

Where:

• I = current in amperes (A)
• t = time in seconds (s)

Given:

• I = 1 A
• t = 60 s

Substitute the values:

Q = 1 × 60 = 60 C

Step 2: Calculate the number of electrons (N)

The number of electrons is given by:

N = Q / e

Where:

• Q = total charge (from Step 1)
• e = charge of one electron (1.60 × 10^-19 C)

Substitute the values:

N = 60 / (1.60 × 10^-19)

Step 3: Perform the calculation

N = 37.5 × 10¹⁹

Step 4: Express in standard scientific notation

N = 3.75 × 10²⁰

Final Answer:

The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is: 3.75 × 10²⁰