The number of electrons in sulphur atom having $\mathrm{n}+\mathrm{l}=3$ are :

Sulphur ( Z = 16) has electronic configuration $=1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^4\cdot \mathrm{n}+\mathrm{l}=3$ is for:

$2\mathrm{p}\text{ because in this case, }\mathrm{n}=2,\mathrm{l}=1.\text{ So, }\mathrm{n}+\mathrm{l}=2+1=3$ Number of electrons in $2p$ sub-shell are 6.

3s because in this case,$\mathrm{n}=3,\mathrm{l}=0.\text{ So, }\mathrm{n}+\mathrm{l}=3+0=3$ Number of electrons in 3s sub-shell are 2 Hence:

Total number of electrons= 6 + 2 = 8. So, true answer is (a)