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The number of electrons involved in the electro deposition of 63.5 g. of Cu from a solution of CuSO₄ is

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answer is C.

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Detailed Solution

1 F deposits 1 eq of Cu from its salt solution.

1 F = charge carried by 6.02 x 10²³ electrons.

1 eq of Cu = 31.75 gm

For the electro deposition of 31.75 gm of Cu =6.02 x 10²³ electrons.

For the electro deposition of 63.5gm of Cu $=frac{{63.5 times 6.02 times {{10}^{23}}}}{{31.75}} = 12.04 times {10^{23}}$

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