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Q.

The number of electrons involved in the reduction of permanganate to manganese dioxide in acidic medium is _________.

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answer is 3.

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Detailed Solution

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$\overset{+ 7}{Mn} O_{4}^{- 1} \to \overset{+ 4}{Mn} O_{2}$
${MnO}_{4}^{- 1} + 4 H^{\oplus} + 3 e^{-} \to {MnO}_{2} + 2 H_{2} O$ Difference in oxidation state = 7-4=3
So number of elements involved =3e^-

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