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Q.

The number of electrons lost or gain during the change,
$Fe + H_{2} O \to {Fe}_{3} O_{4} + H_{2}$

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answer is 8.

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Detailed Solution

$3 Fe + 8 e^{-} \to {({Fe}^{+ \frac{8}{3}})}_{3} (2 H^{+} \to H_{2} + 2 e^{-}) \times 4 3 Fe + 4 H_{2} O \to {Fe}_{3} O_{4} + 4 H_{2} O$

Total number of electrons lost or gained is 8.

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The number of electrons lost or gain during the change,Fe+H2O→Fe3O4+H2