Q.

The number of electrons passing per second through a cross-section of copper wire carrying 10–6 amperes of current per second is found to be

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a

1.6×1019

b

6×1016

c

6×1012

d

6×1035

answer is D.

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Detailed Solution

Charge (coulombs) pass per second =106

Number of electrons passed per second =1061.602×1019=6.24×1012

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