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The number of electrons passing per second through a cross section of copper wire carrying 10^-6 amperes of current is found to be

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$6.25 \times 10^{12}$

$3.2 \times 10^{15}$

$1.6 \times 10^{19}$

$4.5 \times 10^{20}$

answer is D.

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Detailed Solution

Q=ct =10^-6x1=10^-6coulombs

1Coulomb ---6.25 x 10¹⁸e^-

10^-6 coulomb ---? = 6.25 x 10¹²e^-

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