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The number of electrons present in $15.4 g$ of carbon tetrachloride is

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4.452 \times 10^{22} electrons

4.454 \times 1 0^{23} electrons

4.456 \times 1 0^{24} electrons

Both 1 and 2

answer is C.

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Detailed Solution

The number of electrons in

15.4 g

of carbon tetrachloride are

4.456 \times 1 0^{24} .

Number of moles of

CC l_{4} =

\frac{Mass of carbon tetrachloride}{molecular mass of CC l_{4}}

\Rightarrow

\frac{15.4}{154}

\Rightarrow

0.1

moles
1 mole of

CC l_{4} = 6.022 \times 1 0^{23}

molecules
0.1 mole of

CC l_{4}

= 0.1 x 6.022 x 1023 molecules

\Rightarrow

6.022 \times 1 0^{22}

molecules
We know that one molecule of carbon has 6 electrons and one atom of chlorine has 17 electrons.
Therefore,1 molecule of carbon tetrachloride will contain =

6 + (4 \times 17)

\Rightarrow

= 74

electrons.
Number of electrons in

6.022 \times 1 {0^{22}}^{}

molecules of carbon tetrachloride are equal to the product of the number of electrons and Avogadro’s number.

\Rightarrow 74 \times 6.022 \times 1 0^{22}

\Rightarrow 4.456 \times 1 0^{24}

electrons.

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