The number of $F_{2}$ plants similar to $F_{1}$ phenotype and genotypes respectively in a total of 128 plants in $F_{2}$ progeny of a mendelian dihybrid cross are

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48, 32

72, 32

48, 24

72, 48

answer is B.

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Detailed Solution

Concept- A dihybrid cross occurs when two different genes that differ in two observed traits are crossed. Lets assume there are two genes, A and B. Now, suppose AABB and aabb are crossed, so the gametes produced will be AB and ab respectively, which will combine to form AaBb as

F_{1}

progeny.
Now, these

F_{1}

offsprings when crossed with one another, these will produce offspring with the following genotypes-
Question Image

The phenotype of

F_{1}

progeny was, both genes are showing dominant character and its genotype is AaBb.
If we look at the

F_{2}

generation progenies, 9 of the 16 plants produced show phenotypes that are similar to those of the parent plant, (both characters exhibit dominant traits). 4 of these plants share similar genotype with their parent plant.
In question, we have been given a total of 128 plants, so we will apply th evalues that are obtained to us to solve the question further.
Number of