The number of five digit numbers, greater than 40000 and divisible by 5, which can be formed using the digits 0,1,3,5,7 and 9 without repetition, is equal to

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The number of five digit numbers, greater than 40000 and divisible by 5, which can be formed using the digits 0,1,3,5,7 and 9 without repetition, is equal to

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132

120

answer is C.

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Detailed Solution

$Number of ways$
$Case 1 : 5 \times \times \times 0 4 \times 3 \times 2 = 24$
$Case 2 : 7 \times \times \times 0 4 \times 3 \times 2 = 24$
$Case 3 : 7 \times \times \times 5 4 \times 3 \times 2 = 24$
$Case 4 : 9 \times \times \times 0 4 \times 3 \times 2 = 24$
$Case 5 : 9 \times \times \times 5 4 \times 3 \times 2 = 24$
$∴ Total Number of ways = 120$