The number of five-digit positive integers formed using the digits 1,2,3 and 4 only and sum of the digits equal to 10 is_______

5-digited numbers whose sum is to 10
 $$\begin{gathered} 1+2+3+3+1\to \frac{5!}{2!2!}=30 \\ 4+3+1+1+1\to \frac{5!}{3!}=20 \\ 4+2+2+1+1\to \frac{5!}{2!2!}=30 \\ 2+2+2+2+2\to 1 \\ 2+2+2+3+1\to 1\frac{5!}{3!}=20 \end{gathered}$$
 Total = 101