The number of four digited numbers formed by 2, 4, 5, 7, 8 divisible by 4 (when repetition is not allowed ) is

A number is divisible by 4 if last 2 digits of the number is divisible by 4.

Given digits 2, 4, 5, 7, 8 to make the number divisible by 4 the last 2 places can be occupied by 24, 28, 48, 52, 72, 84 (6 ways).

Remaining 2 places can be filled by remaining 3 digits in ${}^3{P}_2$  ways.

$\therefore$  Required number of numbers ${=}^3{P}_2\times 6=36$