The number of Glucose molecules present in 10 ml of decimolar solution is

Given:

• Molarity = 0.1 M
• Volume (\( V \)) = 10 ml = 0.01 litre

Step 1: Calculate Number of Moles

Number of moles = Molarity × Volume (in liters)

= 0.1 × 0.01

= 10^-3 moles

Step 2: Calculate Number of Molecules

Number of Molecules = Moles × Avogadro number (\( N_A \))

= 10^-3 × 6.0 × 10²³

= 6.0 × 10²⁰ molecules

Final Answer

So, the correct option is AA.