The number of gram atoms and weight of an element having  $2\times {10}^{23}$ atoms are (Atomic weight of element is 32.)

$\begin{array}{l}1\text{\hspace{0.17em}mole}\to 6\times {10}^{23}\text{\hspace{0.17em}atom}\to 1\text{\hspace{0.17em}g\hspace{0.17em}atom}\\ 2\times {10}^{23}\text{atom}\to \text{gram\hspace{0.17em}atom}\\ =\frac{2\times {10}^{23}}{6\times {10}^{23}}=\frac{1}{3}=0.33\text{\hspace{0.17em}gram\hspace{0.17em}atom}\\ 1\text{\hspace{0.17em}mole}=6\times {10}^{23}\text{atom}=32\text{\hspace{0.17em}g\hspace{0.17em}of\hspace{0.17em}element}\\ =2\times {10}^{23}\text{atom}=x\text{\hspace{0.17em}g\hspace{0.17em}of\hspace{0.17em}atom}\\ 2\times {10}^{23}\times 32=x\times 6\times {10}^{23}\\ x=\frac{64}{6}=10.63\text{\hspace{0.17em}g\hspace{0.17em}of\hspace{0.17em}element}\end{array}$