The number of grams of oxygen (O2) gas present in 6 × 1010 of oxygen atoms is

6×1010 atoms of 'O' =3×1010O2 molecules; Weight of O2 in grams =3×10106.023×1023×32=1.59×10−12

The number of grams of oxygen (O2) gas present in 6 × 1010 of oxygen atoms is

6×1010 atoms of 'O' =3×1010O2 molecules; Weight of O2 in grams =3×10106.023×1023×32=1.59×10−12

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The number of grams of oxygen (O₂) gas present in 6 × 10¹⁰ of oxygen atoms is

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$1.59 \times 10^{- 12}$

$2.12 \times 10^{- 10}$

$8.48 \times 10^{- 9}$

$4.24 \times 10^{- 11}$

answer is A.

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Detailed Solution

$6 \times 10^{10} atoms of' O' = 3 \times 10^{10} O_{2} molecules;$

$Weight of O_{2} in grams = \frac{3 \times 10^{10}}{6.023 \times 10^{23}} \times 32 = 1.59 \times 10^{- 12}$

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The number of grams of oxygen (O2) gas present in 6 × 1010 of oxygen atoms is

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The number of grams of oxygen (O₂) gas present in 6 × 10¹⁰ of oxygen atoms is