The number of hydrogen atoms present in 25.6 g of sucrose C12H22O11which has a molar mass of 342.3 g is

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The number of hydrogen atoms present in $25.6 g$ of sucrose $(C_{12} H_{22} O_{11})$ which has a molar mass of $342.3 g$ is

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$22 \times 10^{23}$

$44 \times 10^{23} H atoms$

$11 \times 10^{23}$

$9.91 \times 10^{23}$

answer is B.

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Detailed Solution

No. of moles of sucrose $= \frac{25.6}{342.3} = 0.075$

1 mole of sucrose contains $22 \times 6 .023 \times 10^{23} of H - atom$

$0.075$ moles of sucrose contain

$= 9 .91 \times 10^{23} of H - atoms .$

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