The number of hydrogen bonds present in the sequence of a stretch of a double helical DNA $5_{1} A T G C C T A A 3_{1}$ is

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answer is B.

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Detailed Solution

Two hydrogen bonds present between Adenine (A) and Thymine (T) whereas three hydrogen bonds present between Guanine (G) and Cytosine (C). So total hydrogen bonds are 19.

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