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The number of integral values of y for which the chord of the circle $x^{2} + y^{2} = 125$ passing through the point P(8, y) gets bisected at the point P(8, y) and has integral slope is

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answer is B.

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Detailed Solution

$S_{11} = 64 + y^{2} - 125 < 0$

slope of chord $= \frac{8}{y}, \frac{8}{y}$ in integer

$\Rightarrow y^{2} < 61 \Rightarrow - \sqrt{61} < y < \sqrt{61} \Rightarrow y = \pm 1, \pm 2, \pm 4$

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