The number of lone pairs and $\mathrm{S}-\mathrm{S}$ bonds, in ${\mathrm{S}}_8$ molecule, respectively

Sulphur in $S_8$ form,

Electronic configuration of Sulphur $=\left[\mathrm{Ne}\right]3{\mathrm{s}}^{2}3{\mathrm{p}}^{4}3{\mathrm{d}}^0$

Each sulphur has 6 valence electrons and in ${\mathrm{S}}_8$ molecule, each sulphur makes 2 bonds per atom. So number of lone pairs on each sulphur atom $=2$

Total number of lone pairs $=2\times 8=16$

Total number of $\mathrm{S}-\mathrm{S}$ bonds $=8$