The number of lone pairs in ${XeF}_{2}, {XeF}_{4}$ and ${XeF}_{6}$ are respectively

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3,2 and 1

2,2 and 1

1,2 and 3

1,3 and 2

answer is B.

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Detailed Solution

$Xe$ has 8 valence electrons.

In ${XeF}_{2}$ , it has a linear structure. It has two $Xe - F$ bonds lying linear to each other.

The number of lone pairs are 3.

$In {XeF}_{4}$ , it has a square planar structure. The four $Xe - F$ bonds are perpendicular to each other.

The number of lone pairs are 2.

$In {XeF}_{6}$ it has distorted octahedral structure .It has 6 bond pairs and 1 lone pair

Hence, the number of lone pairs in ${XeF}_{2}, {XeF}_{4}$ and ${XeF}_{6}$ are 3, 2 and 1.

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