The number of molecules in $1 cc$ of water is closed to

Density of water is $1 g/c{m}^3$, i.e. $1 c{m}^3=1 g$ of water In 1 g mole or 18 g water there are total $6.02\times {10}^{23}$ molecules.
Hence, in lg of water (or $1 c{m}^3$ of water) number of molecules should be $\frac{6.20\times {10}^{23}}{18}=\frac{1}{3}\times {10}^{23}$