The number of molecules of CO₂ liberated by the complete combustion of 0.1 gram atom of graphite in air is

C + O₂    $\to$    CO₂

1 gram atom      N_A molecules

0.1 g atom           ‘X’ molecules

X =$\frac{0.1 \mathrm{x} {\mathrm{N}}_{\mathrm{A}}}{1}=6.023 \mathrm{x}{10}^{22}$ molecules