The number of molecules present in 1.12×10−5cc of a gas at STP

1 mole gas = 6.02×1023 molecules =22400ccx=1.12×10−5cc⇒x×22400cc=1.12×10−5×6.02×1023 molecules

The number of molecules present in 1.12×10−5cc of a gas at STP

1 mole gas = 6.02×1023 molecules =22400ccx=1.12×10−5cc⇒x×22400cc=1.12×10−5×6.02×1023 molecules

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The number of molecules present in $1.12 \times 10^{- 5} c c$ of a gas at STP

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$3.01 \times 10^{14}$

$3.01 \times 10^{12}$

$6.023 \times 10^{12}$

$6.023 \times 10^{14}$

answer is B.

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Detailed Solution

1 mole gas = $6.02 \times 10^{23}$ molecules $= 22400 c c$

$x = 1.12 \times 10^{- 5} c c$

$\Rightarrow x \times 22400 c c = 1.12 \times 10^{- 5} \times 6.02 \times 10^{23} m o l e c u l e s$

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The number of molecules present in $1.12 \times 10^{- 5} c c$ of a gas at STP