Q.

The number of molecules present in  1.12×105cc of a gas at STP

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a

3.01  ×  1014

b

3.01  ×  1012

c

6.023  ×  1012

d

6.023×1014

answer is B.

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Detailed Solution

1 mole gas = 6.02×1023 molecules =22400cc

x=1.12×105cc

x×22400cc=1.12×105×6.02×1023  molecules

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