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The number of molecules present in 14g of $N_{2}$ molecule is

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6.022 \times 10^{23}

1.51 \times 10^{23}

6.030 \times 10^{23}

3.011 \times 10^{23}

answer is B.

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Detailed Solution

3.011 \times 10^{23}

is the number of molecules present in 14g of

N_{2}

molecule.
The number of moles of

N_{2}

molecule can be calculated by
Moles = given mass/ molar mass
So the number of moles of

N_{2}

molecule with a molar mass of 28g will be

\Rightarrow \frac{14}{28}

\Rightarrow

0.5
Since 1 mole of nitrogen molecule contains

6.023 \times 10^{23}

molecules(Avagadro number)
So the number of nitrogen molecules in 0.5 mole of nitrogen would be

\Rightarrow 0.5 \times 6.023 \times 10^{23}

\Rightarrow 3.011 \times 10^{23}

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