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Q.

The number of molecules present in 2 L of water provided the density of water is


1 gmL-1 is


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a

1 × 1023.molecules of H2O 

b

4 × 1023.molecules of H2O

c

5 × 1023.molecules of H2O

d

6.022 × 1023.molecules of H2O

answer is A.

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Detailed Solution

detailed_solution_thumbnail
The number of molecules present in 2 L of water provided the density of water is
1 gmL-1 is  6.69×1025 molecules of H2O.
⇒1 molar mass of H2O     = 18 g mol-1
1 L of H2O                     = 1000 mL
⇒2 L of H2O                     = 2000 mL
⇒Mass of 2000 mL of H2O= Volume × Density    2000 × 1 =  2000 g
No of moles                   = Mass of substance in grams Molar mass 
                                              = 200018
1 mole of H2O = 6.022 × 1023molecules of H2O
Therefore, no. of molecules of H2O in 2 L of H2O = 2000 18×6.022 ×1023 
= 6.69×1025 molecules of H2O.
Hence, the number of molecules present in 2 L of water provided the density of water is
1 gmL-1 is 6.69×1025 molecules of H2O.
 
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