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The number of molecules present in 2 L of water provided the density of water is

1 gmL-1 is

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1 \times 1 0^{23}

.molecules of

H_{2} O

4 \times 1 0^{23}

.molecules of

H_{2} O

5 \times 1 0^{23}

.molecules of

H_{2} O

6.022 \times 1 0^{23}

.molecules of

H_{2} O

answer is A.

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Detailed Solution

The number of molecules present in 2 L of water provided the density of water is
1 gmL-1 is

6.69 \times 10^{25} molecules of H_{2} O

.
⇒1 molar mass of

H_{2} O

     = 18 g mol-1
⇒1 L of H2O                     = 1000 mL
⇒2 L of H2O                     = 2000 mL
⇒Mass of 2000 mL of

H_{2} O

Volume \times Density

⇒ 2000 × 1 = 2000 g

No of moles = \frac{Mass of substance in grams}{Molar mass}

= \frac{2000}{18}

1 mole of

H_{2} O

6.022 \times 1 0^{23}

molecules of

H_{2} O

Therefore, no. of molecules of

H_{2} O

in 2 L of

H_{2} O

\frac{2000}{18} \times 6.022 \times 10^{23}

6.69 \times 10^{25} molecules of H_{2} O

.
Hence, the number of molecules present in 2 L of water provided the density of water is
1 gmL-1 is

6.69 \times 10^{25} molecules of H_{2} O

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The number of molecules present in 2 L of water provided the density of water is 1 gmL-1 is

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The number of molecules present in 2 L of water provided the density of water is

1 gmL-1 is