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The number of molecules present in 2.2 g of carbon dioxide are:

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1.1 \times 10^{23}

0.3011 \times 10^{23}

2 \times 10^{23}

3 \times 10^{23}

answer is A.

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Detailed Solution

The number of molecules present in 2.2 g of carbon dioxide is

0.3011 \times 10^{23}

.
The molar mass of

C O_{2}

= 44 g/mol.
So, there are

6.022 \times 1 0^{23}

.molecules of

C O_{2}

in 44g.
⇒1 g of

C O_{2}

\frac{6.022 \times 10^{23}}{44}

molecules of

C O_{2}

⇒2.2 g of

C O_{2}

\frac{2.2 \times 6.022 \times 10^{23}}{44}

molecules of

C O_{2}

⇒2.2 g of

C O_{2}

0.3011 \times 10^{23}

molecules of

C O_{2}

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