The number of moles and molecules in 64grams of O2 and the mass of one molecule of O2 are respectively

GMW of one mole of O2=32 gNo of moles of O2 in 64 gx=64×132=2 molesOne mole of O2=6.023×10232 moles of O2=2×6.023×1023 =12.046×1023 moleculesGMW of O2 molecules = 32 gm=wt.of6.023×1023molecules of O2i.e;6.023×1023molecule O2wt=321 molecule O2wt=?16.022×1023×32=5.313×10−23g

The number of moles and molecules in 64grams of O2 and the mass of one molecule of O2 are respectively

GMW of one mole of O2=32 gNo of moles of O2 in 64 gx=64×132=2 molesOne mole of O2=6.023×10232 moles of O2=2×6.023×1023 =12.046×1023 moleculesGMW of O2 molecules = 32 gm=wt.of6.023×1023molecules of O2i.e;6.023×1023molecule O2wt=321 molecule O2wt=?16.022×1023×32=5.313×10−23g

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The number of moles and molecules in 64grams of O₂ and the mass of one molecule of O₂ are respectively

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$1 moles, 2 \times 10^{23} molecules, 5 .313 \times 10^{- 23} g$

$2 moles, 12 .04 \times 10^{23} molecules, 5 .313 \times 10^{- 23} g$

$6 moles, 3 \times 10^{23} molecules, 3 .2 \times 10^{- 23} g$

None of the above

answer is A.

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Detailed Solution

GMW of one mole of $O_{2} = 32 g$
No of moles of $O_{2} in 64 g$
$x = \frac{64 \times 1}{32} = 2 moles$
One mole of $O_{2} = 6 .023 \times 10^{23}$
$2 {moles of O}_{2} = 2 \times 6 .023 \times 10^{23}$
$= 12 .046 \times 10^{23} molecules$
GMW of $O_{2}$ molecules = 32 gm
$= wt . of 6 .023 \times 10^{23} molecules of O_{2}$
$i.e; 6 .023 \times 10^{23} {molecule O}_{2} wt = 32$
${1 molecule O}_{2} wt = ?$
$\frac{1}{6 .022 \times 10^{23}} \times 32 = 5 .313 \times 10^{- 23} g$