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Q.

The number of moles of KMnO4 that are needed to react completely with one mole of ferrous oxalate in acidic solution is

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answer is 0.6.

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Detailed Solution

3KMnO4 + 5FeC2O4 + 24H+  3Mn2+ + 5Fe3+ + 10CO2 +12H2O

KMnO4 = 5 electrons

ferrous oxalate in acidic solution = 3 electrons

while reaction exchange of electrons takes place..........so

3 moles of KMnO4 = 5 moles of FeC2O4

5 moles of FeC2O4 = 3 moles of KMnO4

so 1 mole of FeC2O4 = 3/5 moles of KMnO4

hence 3/5=0.6 moles of KMnO4 will be needed to react completely with one mole of ferrous oxalate in acidic solution.....

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