The number of moles of KMnO₄ that will be needed to react completely with one mole of ferrous oxalate in acidic solution is

$3{\mathrm{KMnO}}_4+5{\mathrm{FeC}}_2{\mathrm{O}}_4+24{\mathrm{H}}^{+}\to 5{\mathrm{Fe}}^{+3}+10{\mathrm{CO}}_2+3{\mathrm{Mn}}^{+2}+3{\mathrm{K}}^{+}+12{\mathrm{H}}_2\mathrm{O}$

From equation, 5moles of ferrous oxalate required 3moles of KMnO₄

The number of moles of KMnO₄ that will be needed to react completely with one mole of ferrous oxalate=$\frac{3}{5}\mathrm{moles}$