The number of moles of ${KNO}_{3} i n 12 \times 10^{23}$ ion pairs of ${KNO}_{3}$ are

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answer is B.

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Detailed Solution

$\begin{array}{l} 1 {mole KNO}_{3} \to 1 mole ion pairs \\ 1 {mole KNO}_{3} \to 6 \times 10^{23} ion pairs \\ x \leftarrow 12 \times 10^{23} \\ x = \frac{12 \times 10^{23}}{6 \times 10^{23}} = 2 {moles of KNO}_{3} \end{array}$

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