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The number of moles present in $1 m^{3}$ of any gas at NTP is

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32.4

54.6

44.6

28.2

answer is C.

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Detailed Solution

22.4 L of any gas contain 1 mole

$\begin{array}{l} or \frac{22 .4}{10^{3}} m^{3} of any gas contain 1 mole \\ ∴ 1 m^{3} of any gas contain \frac{10^{3}}{22 .4} moles = 44 .6 \end{array}$

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