The number of moles present in 6 grams of $\text{KC}l{\text{O}}_3$  are

The gram molecular weight of potassium chlorite is 122.5g.

$122.5\text{g of KC}l{\text{O}}_3\to 1\text{ mole of KC}l{\text{O}}_3$

$6\text{g of KC}l{\text{O}}_3\to \text{? moles of KC}l{\text{O}}_3$

$\frac{1\text{mol}\text{KC}l{\text{O}}_3}{122.5\text{g}\text{of}{\text{KClO}}_{\text{3}}}\times 6\text{g}{\text{of KClO}}_{\text{3}}=0.048\text{mol of}\text{KC}l{\text{O}}_3$ .