The number of N atoms is 681 g of C7H5N3O6 is x×1021 The value of x is ____ (NA=6.02×1023 mol−1)(Nearest Integer)

M M of C7H5N3O6=227 No of moles =681227=3 Moles of n atoms =3×3=9 No of n atoms 9×6.02×1023=5418×1021

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The number of N atoms is 681 g of $C_{7} H_{5} N_{3} O_{6}$ is $x \times 10^{21}$ The value of x is ____ $(N_{A} = 6.02 \times 10^{23} m o l^{- 1})$ (Nearest Integer)

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answer is 5418.

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Detailed Solution

M M of $C_{7} H_{5} N_{3} O_{6} = 227$
No of moles $= \frac{681}{227} = 3$
Moles of n atoms $= 3 \times 3 = 9$
No of n atoms $9 \times 6.02 \times 10^{23} = 5418 \times 10^{21}$

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