Q.

The number of natural numbers, between 212 and 999, such that the sum of their digits is 15, is _____.

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answer is 64.

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Detailed Solution

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Let x = 2  y + z = 13
(4,9), (5,8), (6,7), (7,6), (8,5), (9,4),  6
Let x = 3y + z = 12
(3,9), (4,8), ........, (9,3) 7
Let x = 4  y + z = 11
(2,9), (3,8), ........, (9,1)  9
Let x = 5  y + z = 10
(1,9), (2,8), ........, (9,1) 10
Let x = 6  y + z = 9
(0,9), (1,8), ........, (9,0) 9
Let x = 7  y + z = 8
(0,9), (1,7), ........, (8,0) 9
Let x = 8  y + z = 7
(0,7), (1,6), ........, (7,0)  8
Let x = 9  y + z = 6
(0,6), (1,5), ........, (6,0)  7
Total = 6 = 7 + 8 + 9 + 10 + 9 + 8 + 7 = 64

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