The number of neutrons present in 1.8 gm of $H_{2}O$ is $x.N_A$ then the value of $(x\times 10)$ is_____?

1 molecule of $H_{2}O\to$ 8 neutrons
1 mole of $H_{2}O\to$ 8 moles of neutrons
18 gm $\to$ 8 moles of neutrons
$\begin{array}{l}1.8gm\to ?\\ =\frac{8\times 1.8}{18}=0.8N_A\end{array}$