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Q.

The number of neutrons present in O188 is ____.

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Detailed Solution

The number of neutrons present in O188 is 10.
To find the number of neutrons in the given symbol of an atom, we subtract the number of protons from the mass given in the symbol. For O, the atomic mass is 18, whereas the atomic number is 8. Hence number of neutrons present in it are:
Number of neutrons
=> (18-8) 
=> 10
 
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