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The number of nodel planes is equal to 2, for the valency electron of ?

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Sc⁺² ion

Na⁺ ion

answer is A.

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Detailed Solution

${Sc}^{+ 2} : [Ar] 3 d^{1} 4 s^{0}$

valency electron is present 3d orbital

Number of nodel planes = l = 2

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