The number of normals drawn to the parabola ${\mathrm{y}}^2=4\mathrm{x}$ from the point (1, 0) is

$$\begin{gathered} \mathrm{Given} \mathrm{parabola} {\mathrm{y}}^2=4\mathrm{x} \\ \Rightarrow \overline{)\mathrm{a}=1} \end{gathered}$$

Equation of normal to given parabola is 

$$\begin{gathered} \mathrm{y}=\mathrm{mx}-2\mathrm{am}-{\mathrm{am}}^3 \\ If it passes through the point (1,0) then \\ 0=\mathrm{m}-2\mathrm{m}-{\mathrm{m}}^3 \\ \Rightarrow {\mathrm{m}}^3+\mathrm{m}=0 \\ \Rightarrow \mathrm{m}({\mathrm{m}}^2+1)=0 \\ \Rightarrow \mathrm{m}=0, {\mathrm{m}}^2+1=0 \end{gathered}$$

it has only one real root.

 Number of normals = 1