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The number of ordered pairs of integers (x, y) satisfying the equation x2+6x+y2=4 is

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a
2
b
4
c
6
d
8

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detailed solution

Correct option is D

x2+6x+y2=4(x+3)2+y2=13(x+3,y)=(±3,±2) or (±2,±3)x=0,y=±2,x=6,y=±2x=1,y=±3,x=5,y=±3

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