Q.

The number of ordered 5 - tuple (u,v,w,x,y) where u,v,w,x,y[1,11] which satisfy the inequality  is 2sin2u+3cos2v3sin2w+cos2x5cos2y720 is 

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answer is 432.

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Detailed Solution

Given 
2sin2u+3cos2v3sin2w+cos2x5cos2y720=243251 The equality holds when  sin2u=cos2v=sin2w=cos2x=cos2y=1
⇒∴u,wπ2,3π2,5π2,7π2 x,y,v{π,2π,3π} ⇒∴ no of ordered 5 tuples  =4233=432

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